Lcm of two natural numbers is 590 and their hcf is 59. how many sets o

1.	Lcm of two natural numbers is 590 and their hcf is 59. how many sets of values are possible?
Answer» Since, H.C.F. of the two natural numbers = 59, so we can write - A = 59x and B = 59y Using H.C.F× L.C.M. = Product of two numbers 59x× 59y = 59× 590 ⇒ xy = 10 So, sets of possible numbers are = (1, 10,)(10, 1) and (2, 5)(5, 2) Hence, 4 numbers sets of possible numbers are (59, 590), (590, 59), (118, 295) and (295, 118)

Lcm of two natural numbers is 590 and their hcf is 59. how many sets of values are possible?

Answer»

Since, H.C.F. of the two natural numbers = 59, so we can write -

A = 59x and B = 59y

Using H.C.F× L.C.M. = Product of two numbers

59x× 59y = 59× 590

⇒ xy = 10

So, sets of possible numbers are = (1, 10,)(10, 1) and (2, 5)(5, 2)

Hence, 4 numbers sets of possible numbers are (59, 590), (590, 59), (118, 295) and (295, 118)