Lead is formed from its ore by the following reactions: 2PbS(s)+3O2(g)→2PbO(s)+2SO2(g) (Yield = 40 %)PbO(s)+C(s)→Pb(s)+CO(g) (Yield = 80 %)If 550 kg of PbS was initially taken, find the amount of Pb in kg formed.(Molar mass of Pb=207 g/mol)

Lead is formed from its ore by the following reactions: 2PbS(s)+3O2(g)

1.	Lead is formed from its ore by the following reactions: 2PbS(s)+3O2(g)→2PbO(s)+2SO2(g) (Yield = 40 %)PbO(s)+C(s)→Pb(s)+CO(g) (Yield = 80 %)If 550 kg of PbS was initially taken, find the amount of Pb in kg formed.(Molar mass of Pb=207 g/mol)
Answer» Lead is formed from its ore by the following reactions: $2 P b S (s) + 3 O_{2} (g) \to 2 P b O (s) + 2 S O_{2} (g) (Yield = 40 %)$ $P b O (s) + C (s) \to P b (s) + C O (g) (Yield = 80 %)$ If $550 kg$ of $P b S$ was initially taken, find the amount of $P b$ in kg formed. (Molar mass of $P b = 207 g/mol$ )