Leakage current approximately doubles for every 10°C increase in the – InterviewSolution

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1.	Leakage current approximately doubles for every 10°C increase in the temperature of a transistor has I = 400 nA at 25°C, then its leakage current at 80°C
Answer» ICBO = (400 x 10-9) 2(80-25)/10 = 18 μA.

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