1.

\left[ \begin{array} { c c c } { 1 } & { 3 } & { 1 } \\ { 3 } & { k } & { 6 } \\ { - 1 } & { 5 } & { 1 } \end{array} \right]

Answer»

for A matrix to be non- invertible , The determinant should be zero .

=> 1(k-5*6) -3(3*1+6*1) +4(5*3+k) = 0=>. k-30 -27 +60+4k = 0=> 5k + 3 = 0=> k = -3/5.


Discussion

No Comment Found

Related InterviewSolutions