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\left[ \begin{array} { c c } { x + y } & { 2 } \\ { 5 + z } & { x y } \end{array} \right] = \left[ \begin{array} { l l } { 6 } & { 2 } \\ { 5 } & { 8 } \end{array} \right] |
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Answer» by comparing both the matrixx+y=6 and xy=8 so y=8/xx+8/x=6x*x-6x+8=0(x-2)(x-4)so if x=2 then y=4if x=4 then y=25+z=5 so z=0 thanx |
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