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\left. \begin{array} { c } { \operatorname { cot } 4 \theta ( \operatorname { sin } 5 \theta + \operatorname { sin } 3 \theta ) } \\ { = \operatorname { cot } \theta ( \operatorname { sin } 5 \theta - \operatorname { sin } 3 \theta ) } \end{array} \right. |
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Answer» Lhs = Rhs not prove |
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