\left. \begin{array} { l l } { 3.0 \times 10 ^ { - 3 } } & { ( 2 ) 6.0

1.	\left. \begin{array} { l l } { 3.0 \times 10 ^ { - 3 } } & { ( 2 ) 6.0 \times 10 ^ { - 3 } } \\ { 0.3 \times 10 ^ { - 3 } } & { ( 4 ) 0.6 \times 10 ^ { - 6 } } \end{array} \right.
Answer» The equilibrium for the saturated solution is PbI2 (s) <=> Pb2+ (aq) + 2 I- (aq)and the equilibrium condition is given byKsp = [Pb2+][I-]^2 at equilibrium[Pb2+]= 1.5 x 10^-3 M[I-]= 2 x 1.5 x 10^-3=3.0 x 10^-3 M Ksp = 1.5 x 10^-3 ( 3.0 x 10^-3)^2 =1.4 x 10^-8

\left. \begin{array} { l l } { 3.0 \times 10 ^ { - 3 } } & { ( 2 ) 6.0 \times 10 ^ { - 3 } } \\ { 0.3 \times 10 ^ { - 3 } } & { ( 4 ) 0.6 \times 10 ^ { - 6 } } \end{array} \right.

Answer»

The equilibrium for the saturated solution is

PbI2 (s) <=> Pb2+ (aq) + 2 I- (aq)and the equilibrium condition is given byKsp = [Pb2+][I-]^2

at equilibrium[Pb2+]= 1.5 x 10^-3 M[I-]= 2 x 1.5 x 10^-3=3.0 x 10^-3 M

Ksp = 1.5 x 10^-3 ( 3.0 x 10^-3)^2 =1.4 x 10^-8