InterviewSolution
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InterviewSolution
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\left. \begin{array} { l l } { ( A ) 7 g N _ { 2 } } & { ( B ) 2 g H _ { 2 } } \\ { ( C ) 16 g N O _ { 2 } } & { ( D ) 16 g O _ { 2 } } \end{array} \right. |
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Answer» 7 gm nitrogen = 0.5 mole2gm Hydrogen = 2 moles16gm nitrous = 8/23 moles16gm oxygen = 1 molesince no of molecules directly proportional to the moles=> 2gm of Hydrogen will have more molecules. |
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