\left. \begin{array} { l l l } { \frac { 400 R } { 41 } } & { ( 2 ) \f

1.	\left. \begin{array} { l l l } { \frac { 400 R } { 41 } } & { ( 2 ) \frac { 150 R } { 41 } } \\ { \frac { 41 R } { 400 } } & { ( 4 ) \frac { 300 R } { 41 } } \end{array} \right.
Answer» A temperature above which a gas cannot be liquifies is called critical temperature. Denoted as Tc , where Pc is critical pressure and Vc molar critical volume.Now ,R = 0.082 L atm K-1 mol-1Vc=3b ( according to ideal gas equation )and b =RTc/8Pc= 0.1 Lmol-1Vc = 3RTc/8Pc => Vc = 3400R/8*41 = 150R/41

\left. \begin{array} { l l l } { \frac { 400 R } { 41 } } & { ( 2 ) \frac { 150 R } { 41 } } \\ { \frac { 41 R } { 400 } } & { ( 4 ) \frac { 300 R } { 41 } } \end{array} \right.

Answer»

A temperature above which a gas cannot be liquifies is called critical temperature. Denoted as Tc , where Pc is critical pressure and Vc molar critical volume.Now ,R = 0.082 L atm K-1 mol-1Vc=3b ( according to ideal gas equation )and b =RTc/8Pc= 0.1 Lmol-1Vc = 3*RTc/8Pc

=> Vc = 3*400R/8*41 = 150R/41

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\left. \begin{array} { l l l } { \frac { 400 R } { 41 } } &amp; { ( 2 ) \frac { 150 R } { 41 } } \\ { \frac { 41 R } { 400 } } &amp; { ( 4 ) \frac { 300 R } { 41 } } \end{array} \right.

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\left. \begin{array} { l l l } { \frac { 400 R } { 41 } } & { ( 2 ) \frac { 150 R } { 41 } } \\ { \frac { 41 R } { 400 } } & { ( 4 ) \frac { 300 R } { 41 } } \end{array} \right.