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\left. \begin{array} { l l } { \sqrt { 50 } = 5 \times \sqrt { 2 } } & { \text { (B) } \sqrt { 60 } = 4 \times \sqrt { 15 } } \\ { \sqrt { 243 } = 9 \times \sqrt { 3 } } & { \text { (D) } \sqrt { ( 75 - 10 ^ { 2 } ) } = 5 } \end{array} \right. |
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Answer» The answer is option B √60 = √(15*4) = 2√15 |
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