\left. \begin{array} { l } { \operatorname { log } ( x + 3 ) + \operatorname { log } ( x - 3 ) = \operatorname { log } 16 } \\ { \operatorname { log } ( 3 x + 2 ) - \operatorname { log } ( 3 x - 2 ) = \operatorname { log } 5 } \\ { 2 \operatorname { log } _ { 10 } x = 1 + \operatorname { log } _ { 10 } ( x + ( \frac { 11 } { 10 } ) ) } \end{array} \right.

\left. \begin{array} { l } { \operatorname { log } ( x + 3 ) + \operat

1.	\left. \begin{array} { l } { \operatorname { log } ( x + 3 ) + \operatorname { log } ( x - 3 ) = \operatorname { log } 16 } \\ { \operatorname { log } ( 3 x + 2 ) - \operatorname { log } ( 3 x - 2 ) = \operatorname { log } 5 } \\ { 2 \operatorname { log } _ { 10 } x = 1 + \operatorname { log } _ { 10 } ( x + ( \frac { 11 } { 10 } ) ) } \end{array} \right.
Answer» plz solve this