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\left. \begin{array} { l } { p ( x ) = x ^ { 2 } + x + k } \\ { p ( x ) = k x ^ { 2 } - \sqrt { 2 } x + 1 } \end{array} \right. |
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Answer» if x-1 is the factor , then x = 1 will make p(x) to 0 => p(1) = (1)²+(1)+k = 0 => k+2 = 0 => k = -2 iii) p(1) = k(1)²-√2(1)+1=0 => k = √2-1 |
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