1.

\left. \begin array l p ( y ) = y ^ 2 - y %2B 1 \\ p ( x ) = x ^ 3 \end array \right.

Answer»

i)p(y) = y² - y + 1

p(0) = 0 - 0 + 1 = 1

p(1) = 1² - 1 + 1 = 0

p(2) = 2² - 2 + 1 = 3

iii)p(x) = x³

p(0) = 0

p(1) = 1³ = 1

p(2) = 2³ = 8


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