InterviewSolution
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InterviewSolution
| 1. |
\left| \begin{array}{lll}{y+z} & {x} & {y} \\ {z+x} & {z} & {x} \\ {x+y} & {y} & {z}\end{array}\right|=?\begin{array}{l}{\text { (a) }(x+y+z)(x-z)} \\ {\text { (b) }(x+y+z)(y-z)} \\ {\text { (c) }(x+y+z)(x-z)^{2}} \\ {\text { (d) }(x+y+z)(y-z)^{2}}\end{array} |
| Answer» | |