\left. \begin{array} { r l } { \text { Solve } } & { } \\ { x = } & { – InterviewSolution

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1.

\left. \begin{array} { r l } { \text { Solve } } & { } \\ { x = } & { 4 y - 3 } \\ { x = } & { 2 y + 15 } \end{array} \right.

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the method is x=4y-3x=2y+15_________x-x=4y-2y-3-(+15)=2y-182y=18y=9

x=4y-3…........(1)x=2y+15.........(2)(1)=(2)4y-3=2y+15;2y=18y=9then x=4(9)-3=36-3=33

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