1.

$\left(\frac{2}{\sqrt{6}+2}+\frac{1}{\sqrt{7}+\sqrt{6}}+\frac{1}{\sqrt{8}-\sqrt{7}}+2-2\sqrt{2}\right)$ is equal to :1). 02). $2\sqrt{2}$3). $\sqrt{6}$4). $2\sqrt{7}$

Answer» RIGHT ANSWER for this QUESTION is OPTION 4


Discussion

No Comment Found