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Len n be an odd integer. If `sinn theta=sum_(r=0)^(n) b_(r)sin^(r)theta` for every value of `theta,` thenA. `b_(0)=1, b_(1)=3`B. `b_(0)=0, b_(1)=n`C. `b_(0)=-1, b_(1)=n`D. `b_(0)=0, b_(1)=n^(2)-3n+3` |
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Answer» Correct Answer - B We have, `sinn theta=underset(r=0)overset(n)(sum)b_(r)sin^(r)theta"for all"theta.` Putting `theta=0,` we get ` 0=b_(0)` Again, `sinn theta=underset(r=0)overset(n)(sum)b_(r)sin^(r)theta` `implies(sinntheta)/(sintheta)=underset(r=0)overset(n)(sum)b_(r)(sintheta)r^(r-1)` `impliesunderset(6to0)(lim)(sinntheta)/(sintheta)=underset(r=1)overset(n)(sum)b_(r)underset(thetato0)(lim)(sintheta)^(r-1)` `impliesn =b_(1)` Hence`,_(0)=0and b_(1)=n` |
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