Length of a rectangle exceeds its breadth by 6 meter. If its perimeter

1.	Length of a rectangle exceeds its breadth by 6 meter. If its perimeter is 64 meter then find its length and breadth.
Answer» Let x meter be the breadth of rectangle. Then, length of rectangle = (x + 6) meter ∴Perimeter = 2 (Length + Breadth) = 2 {x + (x + 6)} = 2 (2x + 6) meter According to question, 2(2x + 6) = 64 ⇒ 2x + 6 = 64/2 ⇒ 2x + 6 = 32 ⇒ 2x = 32 – 6 ⇒ 2x = 26 ⇒ x = 26/2 ⇒ x = 13 Hence, the breadth of rectangle = 13 meter length of rectangle = (13 + 6) meter = 19 meter

Length of a rectangle exceeds its breadth by 6 meter. If its perimeter is 64 meter then find its length and breadth.

Answer»

Let x meter be the breadth of rectangle.

Then, length of rectangle = (x + 6) meter

∴Perimeter = 2 (Length + Breadth)

= 2 {x + (x + 6)}

= 2 (2x + 6) meter

According to question,

2(2x + 6) = 64

⇒ 2x + 6 = 64/2

⇒ 2x + 6 = 32

⇒ 2x = 32 – 6

⇒ 2x = 26

⇒ x = 26/2

⇒ x = 13

Hence, the breadth of rectangle = 13 meter length of rectangle = (13 + 6) meter = 19 meter