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Length of an elastic string is x then tension 5N is applied and its length will be y when tension 7 N. What will be its original length ?A. `(2x+y)/(2)`B. `(2y-yx)/(2)`C. `(7x-5y)/(2)`D. `(7y+5x)/(2)`

Answer» Correct Answer - C
`x=L+l_(1) " "therefore l_(1)=x-L`
`y= L+l_(2) " " therefore l_(2) =y-L`
`(F_(2))/(l_(2))=(F_(1))/(l_(1))`
`(7)/(y-L)=(5)/(x-L)" " therefore L=(7x-5y)/(2)`


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