Let 0.8 is the probability that a man aged 90 years will die in a year. If p is the probability that out of 4 men A1,A2,A3 and A4 each aged 90,A1 will die in a year and will be the first to die, then find 10000p48

Let 0.8 is the probability that a man aged 90 years will die in a year

1.	Let 0.8 is the probability that a man aged 90 years will die in a year. If p is the probability that out of 4 men A1,A2,A3 and A4 each aged 90,A1 will die in a year and will be the first to die, then find 10000p48
Answer» Let $0.8$ is the probability that a man aged $90$ years will die in a year. If $p$ is the probability that out of $4$ men $A_{1}, A_{2}, A_{3}$ and $A_{4}$ each aged $90, A_{1}$ will die in a year and will be the first to die, then find $\frac{10000 p}{48}$

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Let 0.8 is the probability that a man aged 90 years will die in a year. If p is the probability that out of 4 men A1,A2,A3 and A4 each aged 90,A1 will die in a year and will be the first to die, then find 10000p48

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