Let [∈0] denote the dimensional formula of the permittivity of the vacuum and [μ0] that of the permeability of the vacuum. If M= mass, L= length, T= time and I= electric current, then:Given F=14π∈0.q1q2r2, where q1 and q2 are charges and r is the distance. Also,c=1√∈0μ0, where c is speed.

Let [∈0] denote the dimensional formula of the permittivity of the v

1.	Let [∈0] denote the dimensional formula of the permittivity of the vacuum and [μ0] that of the permeability of the vacuum. If M= mass, L= length, T= time and I= electric current, then:Given F=14π∈0.q1q2r2, where q1 and q2 are charges and r is the distance. Also,c=1√∈0μ0, where c is speed.
Answer» Let $[\in_{0}]$ denote the dimensional formula of the permittivity of the vacuum and $[μ_{0}]$ that of the permeability of the vacuum. If $M =$ mass, $L =$ length, $T =$ time and $I =$ electric current, then: Given $F = \frac{1}{4 π \in_{0}} . \frac{q_{1} q_{2}}{r^{2}}$ , where $q_{1}$ and $q_{2}$ are charges and r is the distance. Also, $c = \frac{1}{\sqrt{\in_{0} μ_{0}}}$ , where $c$ is speed.

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