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Let ∫(1+x4)dx(1−x4)3/2=f(x)+C1 with f(0)=0 and ∫f(x)dx=g(x)+C2 with g(0)=0. If g(1√2)=πk, then the value of k is |
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Answer» Let ∫(1+x4)dx(1−x4)3/2=f(x)+C1 with f(0)=0 and ∫f(x)dx=g(x)+C2 with g(0)=0. If g(1√2)=πk, then the value of k is |
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