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Let ∫(1+x4)dx(1−x4)3/2=f(x)+C1 with f(0)=0 and ∫f(x)dx=g(x)+C2 with g(0)=0. If g(1√2)=πk, then the value of k is

Answer» Let (1+x4)dx(1x4)3/2=f(x)+C1 with f(0)=0 and f(x)dx=g(x)+C2 with g(0)=0. If g(12)=πk, then the value of k is


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