Let ∫(1+x4)dx(1−x4)32=f(x)+c1 where f(0) = 0 and ∫f(x).dx=g(x)+ – InterviewSolution

1.	Let ∫(1+x4)dx(1−x4)32=f(x)+c1 where f(0) = 0 and ∫f(x).dx=g(x)+c2 with g(0) = 0.If g(1√2)=π2k, then value of k is___
Answer» Let $\int \frac{(1 + x^{4}) d x}{(1 - x^{4})^{\frac{3}{2}}} = f (x) + c_{1}$ where f(0) = 0 and $\int f (x) . d x = g (x) + c_{2}$ with g(0) = 0.If $g (\frac{1}{\sqrt{2}}) = \frac{π}{2 k}$ , then value of k is___

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