1.

Let A = [(1,tanx),(-tanx, 1)] & B = A^(T) A^(-2) if f(x) = det (adj B) then number of solution(s) of the equation 10f(x) – x = 0 is (are) [Note: det(P) denotes the determinant of a square matrix P]

Answer»


Solution :`f(X) = DET (adj)(B)) = |adj (B)| = |B|`
` = |A^(T)||A^(-2)| = |A| 1/(|A|^2)`
`=1/(|A|) = 1/("sec"^2 x) = cos^(2) x`

`10 cos^(2) x - x = 0`


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