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Let `A={1,2}, B={3,6}`and `f: A->B`given by `f(x)=x^2+2 n d g: A->B`given by `g(x)=3xdot`Then we observe that `f a n d g`have the same domain and co-domain. Also we hve, `f(1)=3=g(1)a n d f(2)=6=g(2)dot`Hence `f=gdot` |
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Answer» Clearly, we have dom (f) =dom `(g)={1,2}`. Co-domain of f= co-domain of `g={3,6}`. Also, `f(1)=(3xx1)=3,f(2)=(3xx2)=6,` `g(1)=(1^(2)+2)=3,g(2)=(2^(2)+2)=6` `:.f(1)=g(1)andf(2)=g(2)`. Thus, `f(x)=g(x)" for all "x""inA`. Hence, f=g. |
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