Let →a=17(2^i+3^j+6^k),→b=17(6^i+2^j−3^k),→c=c1^i+c2^j+c−3^k – InterviewSolution

1.	Let →a=17(2^i+3^j+6^k),→b=17(6^i+2^j−3^k),→c=c1^i+c2^j+c−3^k and matrix A=⎡⎢⎢⎢⎣2737676727−37c1c2c3⎤⎥⎥⎥⎦ If AAT=I, then →c is equal to
Answer» Let $\to a = \frac{1}{7} (2^i + 3^j + 6^k), \to b = \frac{1}{7} (6^i + 2^j - 3^k), \to c = c_{1}^i + c_{2}^j + c - 3^k$ and matrix $A = ⎡ ⎢⎢⎢ ⎣ \begin{matrix} \frac{2}{7} & \frac{3}{7} & \frac{6}{7} \frac{6}{7} & \frac{2}{7} & - \frac{3}{7} c_{1} & c_{2} & c_{3} \end{matrix} ⎤ ⎥⎥⎥ ⎦$ If $A A^{T} = I, t h e n \to c$ is equal to

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