Let A = {–2, –1, 0, 2} and f : A → Z: f(x) = x2 – 2x – 3. Fi

1.	Let A = {–2, –1, 0, 2} and f : A → Z: f(x) = x2 – 2x – 3. Find f(A).
Answer» Given : A = {–2, –1, 0, 2} f : A → Z: f(x) = x² – 2x – 3 Finding f(x) for each value of x, f(-2) = (-2)² – 2(-2) – 3 = 4 + 4 -3 = 5 f(-1) = (-1)² – 2(-1) – 3 = 1 + 2 -3 = 0 f(0) = (0)² – 2(0) – 3 = 0 + 0 -3 = -3 f(2) = (2)² – 2(2) – 3 = 4 - 4 -3 = -3 f in ordered pair is represented as f = {(-2,5),(-1,0),(0,-3),(2,-3)}

Let A = {–2, –1, 0, 2} and f : A → Z: f(x) = x2 – 2x – 3. Find f(A).

Answer»

Given :

A = {–2, –1, 0, 2}

f : A → Z: f(x) = x² – 2x – 3

Finding f(x) for each value of x,

f(-2) = (-2)² – 2(-2) – 3 = 4 + 4 -3 = 5

f(-1) = (-1)² – 2(-1) – 3 = 1 + 2 -3 = 0

f(0) = (0)² – 2(0) – 3 = 0 + 0 -3 = -3

f(2) = (2)² – 2(2) – 3 = 4 - 4 -3 = -3

f in ordered pair is represented as

f = {(-2,5),(-1,0),(0,-3),(2,-3)}