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Let →a=2^i−3^j,→b=2^i+^j−6^k. If →r×→a=→r×→b and →r⋅(3^i+4^j+2^k)=2, then the value of →r⋅(5^i+6^j+3^k)= |
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Answer» Let →a=2^i−3^j,→b=2^i+^j−6^k. If →r×→a=→r×→b and →r⋅(3^i+4^j+2^k)=2, then the value of →r⋅(5^i+6^j+3^k)= |
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