Saved Bookmarks
| 1. |
Let a=41/401−1 and for each n≥2, let bn=nC1+nC2⋅a+nC3⋅a2+⋯+nCn⋅an−1. If the value of b2006−b2005 is 4k, where k∈N, then the value of k is |
|
Answer» Let a=41/401−1 and for each n≥2, let bn=nC1+nC2⋅a+nC3⋅a2+⋯+nCn⋅an−1. If the value of b2006−b2005 is 4k, where k∈N, then the value of k is |
|