1.

Let A(4,3),B(-4,3) and C(0,-5) be the vertices of triangle and P(5,0) let L,M and N be the feet of the perpendiculars drawn from P onto the sides BC,CA and AB respectively then

Answer»

<P>area of `Delta LMN` is 5 sq. units
the centroid of `DeltaLMN` does not exist
the ORTHOCENTRE of `DeltaLMN` is the ORIGIN
`L,M` and `N` are collinear

Solution :`P` lies on circumcircle
So `L,M,N` are collinear (i.e. Simson's line)


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