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Let A=⎡⎢⎣630252011⎤⎥⎦ and B be the adjoint of A. Then the value of det(det(A−1)(A2B)T) is |
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Answer» Let A=⎡⎢⎣630252011⎤⎥⎦ and B be the adjoint of A. Then the value of det(det(A−1)(A2B)T) is |
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