Let |A|=|aij|3×3≠0. Each element aij multiplied by ki−j. Let |B| – InterviewSolution

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1.	Let \|A\|=\|aij\|3×3≠0. Each element aij multiplied by ki−j. Let \|B\| be the resulting determinant, where k1\|A\|+k2\|B\|=0. Then k1+k2=
Answer» Let $\| A \| = \| a_{i j} \|_{3 \times 3} \neq 0$ . Each element $a_{i j}$ multiplied by $k^{i - j}$ . Let \|B\| be the resulting determinant, where $k_{1} \| A \| + k_{2} \| B \| = 0. T h e n k_{1} + k_{2} =$

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