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Let A and B ..............

Answer»


Solution :`P(A)=0.3, P(B)=0.4, P(A' nn B')=0.4`
`implies P(AUUB)'=0.4`
`implies P(A UU B)=0.6`
`P(A)+P(B)-P (A nn B)=0.6`
`implies P(A nn B)=0.1` ltbgt `P(A). P(B) NE P(A nn B) implies A & B` are not INDEPENDENT events
`P(A/bar(B))=((A nn bar(B)))/(P(bar(B)))=(P(A)-P(A nn B))/(1-P(B))=0.2/0.6=1/3`
`P(B/bar(A))=(P(B nn bar(A)))/(P(bar(A)))=(P(B)-P(A nn B))/(1-P(A))=0.3/0.7=3/7`


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