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Let A,B,C be angles of triangles with vertex A -= (4,-1) and internal angular bisectors of angles B and C be x - 1 = 0 and x - y - 1 = 0 respectively. Slope of BC is |
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Answer» `1//2` Image of `A(4,-1)` in bisectors of B and C lies on SIDE BC `rArr` Image of `A(4,-1)` with respect to `x-y -1 =0` is `(x-4)/(1) =(y+1)/(-1) =-(2(4+1-1))/(2) rArr (0,3)` Image of `A(4,-1)` with respect to `x -1 =0` is `(x-4)/(1) =(y+1)/(0) =- (2(4-1))/(1) rArr (-2,-1)` Hence, SLOPE of BC is `m = ((3+1)/(0+2)) =2` |
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