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Let a,b,c be positive real numbers. The following system of equations in x,y,z x2a2−y2b2−z2c2=1,−x2a2+y2b2−z2c2=1,−x2a2−y2b2+z2c2=1

Answer»

Let a,b,c be positive real numbers. The following system of equations in x,y,z

x2a2y2b2z2c2=1,x2a2+y2b2z2c2=1,x2a2y2b2+z2c2=1




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