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Let a, b, c, d, e, be real numbers such that a + b < c + d, b + c < d + e, c + d < e + a, d + e < a + b. Then(A) The largest is a and the smallest is b(B) The largest is a and the smallest is c(C) The largest is c and the smallest is e(D) The largest is c and the smallest is b |
Answer» Correct option (A) The largest is a and the smallest is b Explanation: (i) a + b < c + d (ii) b + c < d + e (iii) c + d < e + a (iv) d + e < a + b from (i) & (iii) a + b < e + a ⇒ b < e from (ii) & (iv) b + c < a + b c < a (i) – (ii) a – c < c – e ⇒c > e (i) – (iv) (a – e) + (b – d) < (c – a) + (d – b) from thus d > b (i) + (iii) – (ii c > d overall a is greatest, b is least |
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