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Let a,b,cberealnumbersa ne 0ifalphais a rootsofa^2x^2+ bx+c=0 , betais a rootsofa^2 x^2 -bx-c=0and 0 ltalpha lt beta, thenthe equationa^2 x^2 + 2bx+ 2c=0has a rootgamma hasa root gammathatalwayssatisfies |
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Answer» `GAMMA= ( ALPHA+ BETA )//2` |
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