1.

Let a,b gt 0 and vecalpha=(veci/a+(4hatj)/b+bhatk) and vecbeta = bhati+ahatj+1/bhatk, then the maximum value of 10/(5 + vecalpha.vecbeta) is

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Solution :`vecalpha.vecbeta = b/a+(4a)/(b)+1ge5`
So, `(10/(5 + vecalpha.vecbeta))_("MAX")=1`.


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