1.

Let a, b ∈ R,a≠0, such that the equation, ax2−2bx+5=0 has a repeated root α, which is also a root of the equation x2−2bx−10=0. If β is the other root of this equation, then α2+β2 is equal to:

Answer»

Let a, b R,a0, such that the equation, ax22bx+5=0 has a repeated root α, which is also a root of the equation x22bx10=0. If β is the other root of this equation, then α2+β2 is equal to:



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