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Let 'A' be the area bounded by the curves y^(2) = 4k_(1)x, k_(1) in [1/8, 1/4] x^(2) = 4k_(2) (2-y), k_(2) in [1/4, 1] and y-axis in the first quadrant. Then the least value of A is |
Answer» Required `A=int_(0)^(1)(2-X^(2) -sqrt(x)) DX` `=2-1/3 - 2/3 = 2-1=1` |
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