Let a force →F be acting on a body free to rotate about a point O and let →r be the position vector of any point P on the line of action of the force. Then torque →τ of this force about point O is defined as :→τ=→r×→FGiven, →F=(2^i+3^j−^k) N and →r=(^i−^j+6^k) m. Find the torque of this force.

Let a force →F be acting on a body free to rotate about a point O an

1.	Let a force →F be acting on a body free to rotate about a point O and let →r be the position vector of any point P on the line of action of the force. Then torque →τ of this force about point O is defined as :→τ=→r×→FGiven, →F=(2^i+3^j−^k) N and →r=(^i−^j+6^k) m. Find the torque of this force.
Answer» Let a force $\to F$ be acting on a body free to rotate about a point $O$ and let $\to r$ be the position vector of any point $P$ on the line of action of the force. Then torque $\to τ$ of this force about point $O$ is defined as : $\to τ = \to r \times \to F$ Given, $\to F = (2^i + 3^j -^k) N$ and $\to r = (^i -^j + 6^k) m$ . Find the torque of this force.

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