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Let a force vecF be acting on a body fre to rotate about a point O and let vecr the position vector of any point P on the line of action of th e force . The torque (vec(tau) ) of this force about point O is defined as ,vec(tau)=vecrxxvecF. Given , vecF=(2hati+3hatj-hatk)N "and" vecF=(hati-hatj+6hatk)m . find the torque of this force . |
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Answer» Solution :`VEC(TAU)=vecrxxvecF=|(HATI,HATJ,HATK),(1,-1,6),(2,3,-1)|=hati(1-18)+hatj (12+1)+hatk(3+2)` `vec(tau)=(-17hati+13hatj+5hatk)N-m`. |
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