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Let a function f:[0,5] to R be continuous, f(1)=3 and F be defined as : F(x)=int_(1)^(x)t^(2)g(t)dt, where g(t)=int_(1)^(t)f(u)"du". Then for the function F, the point x=1 is : |
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Answer» a POINT of INFLECTION. |
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