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Let A;G;H be the arithmetic; geometric and harmonic means between three given no. a;b;c then the equation having a;b;c as its root is `x^3-3Ax^2+3G^3/H x-G^3=0` |
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Answer» We have `A = (a + b + c)/(3) implies a + b + c = 34` `G (abc)^(1//3) implies abc = G^(3)` `(1)/(H) = ((1)/(a) + (1)/(b) + (1)/(c ))/(3) = (ab + bc + ca)/(3abc)` `implies (3G^(3))/(H) = ab + bc + ca` The equation having a, b and c as its roots is `x^(3) - (a + b+ c) x^(2) + (ab + bc + ca) x - abc = 0` or `x^(3) - 3Ax^(2) + (3G^(3))/(H) x - G^(3) = 0` |
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