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Let a=min{x2+2x+3:x∈R} and b=limθ→01−cosθθ2. Then n∑r=0arbn−r is |
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Answer» Let a=min{x2+2x+3:x∈R} and b=limθ→01−cosθθ2. Then n∑r=0arbn−r is |
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