Let a point P moves such that the sum of squares of it's distance from the planes P1:x−y−z=0 and P2:y−z=0 is always equal to the square of it's distance from the plane P3:x−2y+z=0. Then the locus of point P is:

Let a point P moves such that the sum of squares of it's distance from

1.	Let a point P moves such that the sum of squares of it's distance from the planes P1:x−y−z=0 and P2:y−z=0 is always equal to the square of it's distance from the plane P3:x−2y+z=0. Then the locus of point P is:
Answer» Let a point $P$ moves such that the sum of squares of it's distance from the planes $P_{1} : x - y - z = 0$ and $P_{2} : y - z = 0$ is always equal to the square of it's distance from the plane $P_{3} : x - 2 y + z = 0.$ Then the locus of point $P$ is:

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Let a point P moves such that the sum of squares of it's distance from the planes P1:x−y−z=0 and P2:y−z=0 is always equal to the square of it's distance from the plane P3:x−2y+z=0. Then the locus of point P is:

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