Saved Bookmarks
| 1. |
Let a tangent be drawn at a point on the focus f(x,y) = 0 and it meets the positive X and Y- axes at point P and Q. Let A and G be respectively the arithmetic and geometric means of the segments OP and OQ. Now, If A=1 then the locus f(x, y) = 0, is (A) x = Y/k +2/(1-K), (where 'k' is a parameter) |
|
Answer» `X = y/k + 2/1-k, `(where 'k' is a PARAMETER) |
|