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Let A={x∈R:x2+(m−1)x−2(m+1)=0} and B={x∈R:(m−1)x2+mx+1=0}, where m∈R. If A∪B has exactly three distinct elements, then the number of possible values of m is |
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Answer» Let A={x∈R:x2+(m−1)x−2(m+1)=0} and B={x∈R:(m−1)x2+mx+1=0}, where m∈R. If A∪B has exactly three distinct elements, then the number of possible values of m is |
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