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Let A={x:(x−1)(x2−10+21)=0} and B={y:y is a prime factor of 42}, then the number of common elements between A×B and B×A is

Answer» Let A={x:(x1)(x210+21)=0} and B={y:y is a prime factor of 42}, then the number of common elements between A×B and B×A is


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