Let a1=2, an+1=a2n−an+1 for n≥1, then ∞∑n=11an is – InterviewSolution

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1.	Let a1=2, an+1=a2n−an+1 for n≥1, then ∞∑n=11an is
Answer» $Let a_{1} = 2, a_{n + 1} = a_{n}^{2} - a_{n} + 1 for n \geq 1, then \infty \sum n = 1 \frac{1}{a_{n}} is$

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